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7y^2+51y+14=0
a = 7; b = 51; c = +14;
Δ = b2-4ac
Δ = 512-4·7·14
Δ = 2209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2209}=47$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(51)-47}{2*7}=\frac{-98}{14} =-7 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(51)+47}{2*7}=\frac{-4}{14} =-2/7 $
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